SQL Datums Herausforderung

[ExAzubi]

Als schnelle Idee: Common table expressen

USe X with AS (
Select KEY AS A, Count(KEY) from Bestand left join on DATUMDATEI on BDAT = DDAT and BSTAT = TRUE GROUP BY KEY, ORDER BY KEY HAVING COUNT(KEY) >=4)

Select * from BESTAND inner JOIN X on Bestand.key = X.KEY

oder so...

[Pikachu]

Vielleicht so?

SELECT   DISTINCT BB.* FROM Bestand BB, Bestand B1, Bestand B2, Bestand B3

WHERE    BB.STATUS=1
AND      B1.STATUS=1 AND B1.DATUM = BB.DATUM + 1 DAY
AND      B2.STATUS=1 AND B2.DATUM = BB.DATUM + 2 DAYS
AND      B3.STATUS=1 AND B3.DATUM = BB.DATUM + 3 DAYS

ORDER BY BB.DATUM 

[Fuerchau]

select Artikel, Count(*)
from bestand b
inner join Kalender k on k.tag between b.tag and b.tag + 3 days
where b.tag = 'Irgendeintag'
and b.status = true
Group by Artikel
having Count(*) = 4


So ähnlich könnte es gehen.

[B.Hauser]

Ich würde Baldurs SQL noch etwas modifizieren:

With x as (Select c.datum
             From Calendar c join Bestand b 
                  on b.Datum between     c.Datum and c.datum + 3 Days  
                                     and TrueFalse = 1    
             Group by c.Datum
             Having Count(c.Datum) >= 4)
Select b.* 
from x join Bestand b on x.Datum = b.Datum and TrueFalse = 1

Birgitta